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Magnetism and Matter · two topics outside the current syllabus · deep dive

Heat and Memory

Two things can happen to a magnetic material that ordinary formulas cannot describe. Heat can undo its magnetism, in a way captured by a single elegant law. And iron can remember where it has been, in a way captured by a loop rather than a line. This page builds both from the atoms upwards.

Field versus heatMeasure the constantMap the phasesWalk the loopDesign a material
Gap content — still asked
Curie's law χ = C/T

The rationalised NCERT gives only the qualitative statement that cooling raises magnetisation. The equation is not in the book, but it has been set as AIPMT 2003 and JEE Main 2019, and appears throughout coaching material. Learn the formula and the ratio method; that is enough.

Deleted from NEET and JEE Main
Hysteresis

Removed from the rationalised NCERT and from the JEE Main syllabus. It survives in older question banks and is live for KCET, MHT-CET, WBJEE, EAMCET, BITSAT and several state boards. For NEET 2027, read for recognition; do not drill.

Why they belong on one page anyway

They are the same physics seen from two sides. Curie's law describes what heat does to magnetic order — it destroys it, smoothly and reversibly. Hysteresis describes what happens when order is hard to move — the material lags, and the lag costs energy that turns into heat.

One is heat defeating order. The other is order refusing to move, and generating heat as a result. Understanding either one makes the other easier.

PART 01

Field versus heat — the tug of wargap content

Where the 1/T comes from, before any algebra
Story

Lining up children on a windy day

You are trying to line up a class of children facing the front. You have a megaphone — that is the magnetic field, and the louder you shout, the more of them face you.

But the room is full of distractions: a wasp, someone's dog, a firework outside. That is heat. The more chaos, the more children get knocked out of line.

What actually decides the outcome is not the megaphone alone, or the chaos alone. It is the ratio of one to the other. A quiet whisper in a silent room beats a shout in a hurricane.

That ratio is the whole of Curie's law. Alignment depends on field divided by temperature — which is exactly why the temperature ends up in the denominator.

Lab 1 · The tug of war

two knobs, one ratio

The left bar is the aligning energy the field offers each dipole. The right bar is the thermal energy trying to scramble it. Only their ratio matters — try to prove that by finding two different settings that give the same alignment.

Aligning energy mB: Thermal energy kT: Ratio x = mB/kT: Alignment: Regime:

Push the field high and the temperature low and the alignment approaches 100% — saturation. Notice that Curie's law breaks down there: it only holds while alignment is small, which means while mB is much less than kT.

The honest version, for the curious

The full theory says the fraction aligned follows the Langevin function of the ratio x = mB/kT. For small x it simplifies to roughly x/3, giving

M ≈ n m2B / (3k T)  ⇒  χ = μ0 n m2 / (3k T) = C/T

You are not required to derive this. But it does show two useful things: the Curie constant C is built from real material properties (how many dipoles per cubic metre, and how strong each is), and the law is an approximation valid in weak fields. In a strong enough field at low enough temperature, saturation takes over and χ stops meaning anything.

PART 02

The law itselfgap content

χ = C/T · and the three ways it gets asked
χ = C / T   ⇒   χT = C = constant
Maths

Everything you need from one line

Form 1 — proportionality. χ ∝ 1/T. Double the temperature, halve the susceptibility.

Form 2 — constant product. Since χT = C for the material, two states are linked by χ1T1 = χ2T2. This is the one to use in exams, because you never have to find C.

Form 3 — magnetisation. Combining with M = χH gives M ∝ B/T. Field helps, heat hinders, and they appear on opposite sides of the fraction.

The Curie constant C carries the unit kelvin, because χ is dimensionless and C = χT. Deriving the unit from the equation is always safer than recalling it.

Three rules that turn this into marks

1. Convert to kelvin, every time. A question quoting 27°C and 227°C means 300 K and 500 K. The ratio 300/500 is nothing like 27/227, and this single slip has ruined more answers than the physics ever has.

2. Check the direction before the arithmetic. Cooling must raise χ; heating must lower it. That check alone usually eliminates three of four options.

3. Never compute C unless asked. The constant-product form does the job in one line.

Quick check

A paramagnetic sample has χ = 4 × 10−4 at 27°C. At 327°C its susceptibility is

PART 03

How the constant is actually measuredgap content

Straightening a curve into a line
Story

Why scientists hate curves

Suppose you measure χ at several temperatures and plot it against T. You get a curve. Curves are hard — it is difficult to tell a good curve from a slightly wrong one just by looking.

So do something clever: plot χ against 1/T instead. Because χ = C × (1/T), that turns the law into y = mx — a straight line through the origin. And human eyes are excellent at spotting whether points lie on a straight line.

Better still, the slope of that line is C. You have not just tested the law, you have measured the constant.

Lab 2 · Measure the Curie constant

take readings, fit a line

Press Take a reading to measure χ at a random temperature, with a little experimental scatter. The left panel plots χ against T; the right plots the same data against 1/T. Watch which one is easier to judge.

Readings: 0 Fitted slope: True value: hidden Error:

Take three readings and fit; then take ten more and fit again. More data means the scatter averages out and the slope converges on the true constant — which is exactly why real experiments repeat measurements.

The graph question, in both directions

PlotShape for a paramagnetWhat the slope means
χ against TFalling curve, always above the axis, approaching zeroNot constant — no simple reading
χ against 1/TStraight line through the originSlope = C, the Curie constant
1/χ against TStraight line through the originSlope = 1/C

Exam questions give you one of these three and ask for the shape, or give the shape and ask which is plotted. Read the axis labels before choosing. Both χ-vs-T and χ-vs-1/T appear as options in the same question precisely to catch a hurried reading.

PART 04

The whole temperature mapgap content

Curie's law, Curie–Weiss, and the ferromagnetic region

Lab 3 · The phase map

drag the temperature

One material, the full temperature range. Below the Curie point it is ferromagnetic with a huge susceptibility; above it, the same material follows Curie–Weiss and behaves as a paramagnet.

T = K TC = K Phase: χ ≈ Law in force:

Drag T down towards TC from above and watch χ blow up. That divergence is the material deciding to magnetise itself without any help — the birth of spontaneous magnetisation.

Below TC: ferromagnetic, χ ≫ 1 · Above TC: χ = C/(T − TC)

Real Curie temperatures worth knowing

MaterialCurie temperatureNote
Cobalt≈ 1394 K (1121°C)The highest of the common ferromagnets
Iron≈ 1043 K (770°C)Red-hot iron is no longer magnetic
Nickel≈ 631 K (358°C)A hot oven would do it
Gadolinium≈ 293 K (20°C)Magnetic in your fridge, not in your hand

Gadolinium is the memorable one: its Curie point sits at ordinary room temperature, so it is ferromagnetic on a cold day and paramagnetic on a warm one. It is the reason gadolinium appears in NCERT's list of ferromagnetic elements alongside iron, cobalt and nickel.

The Curie–Weiss trap

Above TC the law is χ = C/(T − TC), not C/T. In a ratio problem you must subtract TC first and then treat the two differences as ordinary temperatures.

Worked instance: TC = 300 K, χ = 4 × 10−3 at 400 K, find χ at 500 K. The differences are 100 K and 200 K — a factor of 2 — so χ halves to 2 × 10−3. Using plain Curie's law would have given 3.2 × 10−3, and that wrong answer is always among the options.

PART 05

Why iron remembersdeleted

Domain walls that get stuck
Story

Dragging a heavy rug across a rough floor

Push a heavy rug across a floor with splinters and nail heads. It does not glide. It catches, resists, then suddenly jerks forward when you push hard enough. And when you stop pushing, it does not slide back — it stays where the last jerk left it.

Inside a piece of iron, the boundaries between domains — the domain walls — behave exactly like that rug. Impurities, grain boundaries and crystal defects act as the splinters. Walls get pinned.

So when you switch the field off, the walls do not slide back to where they started. Some magnetism stays behind. The iron remembers.

And every jerk wastes a little energy as heat — the same way dragging the rug warms the floor. That waste is the loop area.

Three consequences, all from one cause

Retentivity exists because walls stay pinned when the field is removed. If walls glided freely, B would return to zero and there would be no permanent magnets at all.

Coercivity exists because you must push hard enough in reverse to unpin them again.

Energy loss exists because unpinning is irreversible — the energy spent does not come back. It leaves as heat.

Pinning is why a material is hard or soft. Many defects ⇒ strongly pinned ⇒ hard. Few defects ⇒ walls move freely ⇒ soft. That is genuinely why soft iron is purified and annealed, while permanent magnets are deliberately made from complicated alloys.

PART 06

Walking the loop, stage by stagedeleted

What the domains are doing at every point on the curve

Lab 4 · The loop walker

the domains, live

Left is the B–H curve with your position marked. Right shows what the domains inside the material are doing at that exact moment. Step through the full journey and the loop stops being a shape and starts being a story.

Stage: H = B = Domains:

Note that the very first climb — from unmagnetised iron up to saturation — happens along a curve that is never travelled again. That is the initial or virgin magnetisation curve, and once you have saturated the sample you cannot get back onto it without demagnetising completely.

PointHBNameWhat the domains are doing
O00Virgin stateRandom directions, cancelling exactly
a+Hmax+BsSaturationAll aligned right; nothing left to align
b0+BrRetentivityMostly still aligned — walls pinned in place
c−Hc0CoercivityHalf left, half right — net zero, but not random
d−Hmax−BsReverse saturationAll aligned left
e0−BrReverse retentivityMostly still aligned left
f+Hc0Reverse coercivityHalf and half again

Anchor each term to an axis and you cannot confuse them

Retentivity is the B-axis intercept — the value of B when H = 0. What is retained.

Coercivity is the H-axis intercept — the value of H when B = 0. The coercion needed to erase it.

Point c is subtle and worth pausing on. B = 0 there, but the material is not back to its virgin state. At O the domains were random; at c they are split into two opposing halves that happen to cancel. Same reading, completely different internal condition — which is precisely what "the material remembers" means.

Quick check

At point c on the loop, B = 0. Compared with the original unmagnetised state at O, the material is

PART 07

The area is the energydeleted

W = ∮H dB per unit volume per cycle
Maths

Why the enclosed area means heat

To change the magnetisation of unit volume by dB, the source must supply work dW = H dB. Over one complete cycle:

Wcycle = ∮ H dB = area enclosed by the B–H loop

If the path retraced itself the outward and return integrals would cancel and the total would be zero. Because the path does not retrace, a non-zero area remains — and that leftover is energy that never comes back. It leaves the material as heat.

Check the units. H is in A m−1 and B is in T. Their product is A m−1 × T = J m−3 — energy per unit volume. The axes themselves tell you the area is an energy density.

In a transformer running at 50 Hz, this loss occurs fifty times a second, continuously, for as long as the device is switched on. Which is why the loop area is not an academic curiosity but a design specification.

A trick worth carrying: area on a graph is almost always energy

Under a force–displacement curve, area is work. Under a pressure–volume curve, area is work. Enclosed by a B–H loop, area is energy lost per cycle per unit volume.

When you meet an unfamiliar graph, multiply the units of the two axes together. If you get joules, or joules per something, the area is an energy.

PART 08

Design a material for a jobdeleted

Hard, soft, and the middle ground

Lab 5 · The loop designer

build it, then find its job

Set the coercivity and retentivity yourself and watch the loop reshape. The verdict tells you what your invented material would actually be good for — and what it would be terrible at.

Loop area: Classification: Good for: Bad for:

Try the three presets in turn. Note that recording media sit deliberately in the middle — retentive enough to hold data for years, but not so coercive that a write head cannot change it.

RequirementLoop shapeCoercivityRetentivityMaterial
Transformer coreNarrow, small areaLowLow–moderateSoft iron, silicon steel
Electromagnet coreNarrow, tallLowLowSoft iron
Permanent magnetBroad, large areaHighHighAlnico, lodestone
Magnetic recordingFairly broad, squarishModerateHighIron oxide, chromium oxide

The one-question test

Faced with any application, ask: must this material hold on, or let go?

Hold on ⇒ hard ⇒ broad loop, high coercivity, high retentivity. Permanent magnets, recording media.
Let go ⇒ soft ⇒ narrow loop, low coercivity, small area. Transformers, electromagnets.

Note that "high permeability" and "low retentivity" are not contradictory, though students often reject that combination as impossible. Permeability describes the response while a field is applied; retentivity describes what remains after it is removed. Soft iron has both, and that is exactly why it makes a good electromagnet.

PART 09

Worked problems

Real past questions in the standard format
Curie's law ratio · JEE Main 2019 (12 Jan)
Given
A paramagnetic material has χ = 2.8 × 10−4 at 350 K.
Asked
Its susceptibility at 300 K.
Concept
Curie's law makes χT constant, so the two states are linked by an inverse proportion. C never needs computing.
Formula
χ1T1 = χ2T2
Solution
χ2 = χ1(T1/T2) = 2.8 × 10−4 × (350/300)
350/300 = 7/6 ≈ 1.1667
χ23.267 × 10−4
Direction check
Cooling from 350 K to 300 K, so χ must rise. It did. Any option below 2.8 × 10−4 could have been eliminated on sight.
Curie–Weiss ratio · typical JEE pattern
Given
A ferromagnet with Curie temperature 300 K has χ = 4 × 10−3 at 400 K.
Asked
Its susceptibility at 500 K.
Concept
Above TC the material follows Curie–Weiss. Work with (T − TC) throughout, not T.
Formula
χ1(T1 − TC) = χ2(T2 − TC)
Solution
T1 − TC = 400 − 300 = 100 K
T2 − TC = 500 − 300 = 200 K
The difference doubled, so χ halves:
χ2 = 2 × 10−3
Trap
Using plain Curie's law gives 4 × 10−3 × (400/500) = 3.2 × 10−3. That wrong answer is always among the options. Subtract TC first.
Demagnetising current from coercivity · JEE Main 2014
Given
Coercivity Hc = 3 × 103 A m−1. Solenoid of length 10 cm with 100 turns.
Asked
The current needed to demagnetise the magnet placed inside.
Concept
Coercivity is quoted in A m−1 — the units of H. So it equates directly to the solenoid's magnetic intensity. No μ0 anywhere.
Formula
Hc = nI, with n = N/L
Solution
n = 100/0.10 = 1000 turns per metre
I = Hc/n = 3 × 103/1000 = 3 A
Family
JEE Main 2024: Hc = 5 × 103, L = 30 cm, N = 150 → n = 500, I = 10 A. JEE Main 2019 runs it backwards: L = 0.2 m, N = 100, I = 5.2 A → Hc = 2600 A m−1.
Signal
Units in A m−1 mean H. If μ0 has appeared in your working on this type, you have taken a wrong turn.
Reading a B–H curve · JEE Main 2020 (7 Jan)
Given
An experimentally measured B–H loop for a ferromagnetic material.
Asked
Where to read retentivity, coercivity and saturation.
Concept
Each quantity is an intercept or an extreme value. Anchoring each to its axis removes all ambiguity.
Solution
Retentivity = value of B when H = 0 — the vertical intercept.
Coercivity = value of H when B = 0 — the horizontal intercept.
Saturation = the maximum value of B, where the curve flattens.
Fourth quantity
The enclosed area is the energy lost per cycle per unit volume — often asked in the same question as a separate part.
PART 10

Everything on one page

Both topics, compressed
Curie: χ = C/T · χ1T1 = χ2T2 · M ∝ B/T · [C] = K Curie–Weiss (T > TC): χ = C/(T − TC) · diverges at TC χ vs 1/T is a straight line of slope C · 1/χ vs T is a straight line of slope 1/C Hysteresis: retentivity = B at H=0 · coercivity = H at B=0 · area = energy/cycle/volume

Six sentences that carry both topics

1. Alignment depends on the ratio of field energy to thermal energy, which is why T ends up in the denominator.
2. χT is a constant, so two states link by simple inverse proportion — and always convert to kelvin first.
3. Plot χ against 1/T to straighten the law; the slope is C.
4. Above the Curie point a ferromagnet obeys Curie–Weiss, and the TC must be subtracted before any ratio.
5. Hysteresis exists because domain walls get pinned on defects — retentivity, coercivity and energy loss all come from that one cause.
6. Loop area is energy lost per cycle per unit volume: narrow for transformers, broad for permanent magnets.

An honest word on priority

Neither of these topics is in your NEET or JEE Main syllabus. Curie's law is at least still set in practice papers and has appeared in past papers, so learning χ = C/T and the ratio method is a sensible half-hour. Hysteresis is deleted from both, and beyond knowing what retentivity, coercivity and loop area mean, further time on it will not pay.

If you are also sitting KCET, MHT-CET, WBJEE, EAMCET or BITSAT, both are live and this page is worth working through properly — particularly Lab 4, since loop-reading questions are common in those papers.

Otherwise: read it once for understanding, do the four worked problems, and put your remaining hours into torque and energy, which carry several times the marks of everything on this page combined.