Current Electricity · Question-type atlas

The Metre
Bridge

Every question type NEET 2027 can set on this instrument, sorted A to F and ranked by how likely you are to meet it. Each type carries its shortcut; the drilled ones carry worked problems.

In syllabus: Wheatstone bridge · Metre bridge Removed: Potentiometer · Carbon resistor colour code

Slide the jockey

Where you balance decides how good the reading is

left gap · R right gap · X
Balance length ℓ
50 cm
Segments
50 : 50
Ratio R / X
1.00
Error, Δℓ = ±1 mm
0.40 %
Sensitivity index
25.0 / 25

Best possible reading. Error is at its minimum and the null is easiest to detect.

Formula sheet

Everything above reduces to these. R sits in the left gap, X in the right, ℓ is measured from the left end.

Balance condition
R / X = ℓ / (100 − ℓ)Each gap is proportional to the wire segment on its own side.
Solve for the unknown
X = R (100 − ℓ) / ℓ
Solve for the length
ℓ = 100 R / (R + X)Fastest route for any forward problem.
Interchange the gaps
new ℓ = 100 − ℓ
shift = |100 − 2ℓ|
Series addition (arm s)
arm → R + sNull moves away from that gap.
Shunt (parallel S)
arm → R S / (R + S)
to reach target T: S = X T / (X − T)Null moves toward that gap.
Scaling a gap
m = ℓ / (100 − ℓ)
R ×a, X ×b ⟹ m′ = (a/b) m
ℓ′ = 100 m′ / (m′ + 1)
Fractional error
|ΔX / X| = 100 Δℓ / [ ℓ (100 − ℓ) ]Minimum at ℓ = 50 cm. At the centre it is simply 4Δℓ percent, Δℓ in cm.
Sensitivity
dℓ / (dX/X) = ℓ (100 − ℓ) / 100Same product as the error, but on top instead of underneath.
Centring the null
factor = (100 − ℓ) / ℓ
% change = [(100 − 2ℓ) / ℓ] × 100
End corrections
R / X = (ℓ + α) / (100 − ℓ + β)Two readings with the gaps swapped cancel the end error.
Resistivity from X
ρ = X A / L = X π r² / L