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Class 12 · Chapter 4 · NEET Drill Pack

Moving Charges and Magnetism

📄 NCERT source: leph104.pdf · Class 12 Physics Ch 4  ·  🎯 Study plan: How to Prepare (5-day pass · 3 pillars · direction drill)

A PYQ-weighted, formula-first mastery pack — Biot-Savart, Ampere's law, Lorentz force, cyclotron, galvanometer. Every formula tagged with SI unit + applicability condition. 🔥 flags the highest-yield items NEET repeats every year.

📅 Built: 2026-07-26

📚 Core Topics — Conceptual Anchors 60-second scan

The chapter builds from the microscopic picture (force on a single moving charge) → circuit-level machinery (galvanometer, cyclotron). Twelve conceptual anchors — a scan of them gives you the whole chapter shape before diving into formulas.

1 Lorentz force

Total EM force on a moving charge is the sum of electric and magnetic parts. Only the electric part does work.

\[\mathbf F = q(\mathbf E + \mathbf v \times \mathbf B)\]

2 Circular motion in B

When \(\mathbf v \perp \mathbf B\), qvB supplies centripetal force. Speed and KE stay constant — direction changes only.

\[r = \dfrac{mv}{qB},\quad T = \dfrac{2\pi m}{qB}\]

3 Helical path & velocity selector

Angled \(\mathbf v\) gives a helix (r from \(v_\perp\), pitch from \(v_\parallel\)). Crossed E and B pass one v undeviated.

\[\text{pitch} = \dfrac{2\pi m v\cos\theta}{qB},\quad v_{\text{sel}} = \dfrac{E}{B}\]

4 Cyclotron

Period is independent of v (T = 2πm/qB) — a fixed-frequency AC voltage between the dees keeps ions in resonance every half-cycle.

\[f_c = \dfrac{qB}{2\pi m},\quad K_{\max} = \dfrac{q^2 B^2 R^2}{2m}\]

5 Biot–Savart law

Every current element contributes a small \(d\mathbf B\). Direction by \(d\mathbf l \times \hat r\); magnitude falls as 1/r².

\[d\mathbf B = \dfrac{\mu_0}{4\pi}\dfrac{I\,d\mathbf l \times \hat r}{r^2}\]

6 Field of a straight wire

Field lines are concentric circles by right-hand thumb rule. \(\mu_0/(4\pi) = 10^{-7}\) T·m/A.

\[B = \dfrac{\mu_0 I}{2\pi a}\]

7 Field of a circular loop

At centre: 2R, not 2πR. Loop acts as a magnetic dipole far along its axis.

\[B_{\text{c}} = \dfrac{\mu_0 N I}{2R},\; B_{\text{axis}} = \dfrac{\mu_0 N I R^2}{2(R^2+x^2)^{3/2}}\]

8 Ampère's circuital law

Line integral of B around any closed loop = μ₀ × enclosed current. Always true; only useful when symmetry lets you pull B out of the integral.

\[\oint \mathbf B\cdot d\mathbf l = \mu_0 I_{\text{enc}}\]

9 Solenoid & toroid

Long solenoid: uniform inside, zero outside; μ₀nI/2 at each end. Toroid: field only inside the ring, zero elsewhere.

\[B_{\text{sol}} = \mu_0 n I,\quad B_{\text{tor}} = \dfrac{\mu_0 N I}{2\pi r}\]

10 Force on current-carrying wire

Perpendicular to both I and B. Net force on any closed loop in uniform B = 0.

\[\mathbf F = I\mathbf L \times \mathbf B,\quad F = BIL\sin\theta\]

11 Force between parallel wires

Same-direction currents attract; opposite currents repel. Definition of ampere: 2×10⁻⁷ N/m between two 1-A wires 1 m apart.

\[\dfrac{F}{L} = \dfrac{\mu_0 I_1 I_2}{2\pi d}\]

12 Torque, magnetic moment & MCG

Loop in B feels torque (max when plane ∥ B). Moving-coil galvanometer converts to ammeter (parallel shunt) or voltmeter (series R).

\[\boldsymbol\tau = \mathbf m \times \mathbf B,\; m = NIA,\; U = -\mathbf m\cdot\mathbf B\]

🧮 NEET Formula Bank — Every Formula, Grouped

Every formula NEET could test from this chapter, organised into seven alphabetical sub-groups. Each formula card carries symbols · SI unit · condition. Use as reference / final-week sheet.

A · Force on Charged Particles

1 Lorentz force

Total EM force on a moving charge

\[\mathbf F = q(\mathbf E + \mathbf v \times \mathbf B)\]

q in C · v in m/s · B in T · magnetic part is ⟂ v, so it does no work.

N

2 Radius (v ⟂ B)

Four equivalent forms

\[r = \dfrac{mv}{qB} = \dfrac{p}{qB} = \dfrac{\sqrt{2mK}}{qB} = \dfrac{1}{B}\sqrt{\dfrac{2mV}{q}}\]

Use the form matching the given quantity: v · p · K · V.

m

3 Period · frequency · angular frequency

All independent of v and r

\[T = \dfrac{2\pi m}{qB},\; f = \dfrac{qB}{2\pi m},\; \omega = \dfrac{qB}{m}\]

Fast particles trace bigger circles in the same time — cyclotron principle.

s · Hz · rad/s

4 Helical pitch

v at angle θ to B

\[\text{pitch} = v\cos\theta \cdot T = \dfrac{2\pi m v\cos\theta}{qB}\]

Radius uses only v sin θ; pitch uses only v cos θ.

m

5 Velocity selector

Crossed E and B

\[v = \dfrac{E}{B}\]

Undeviated regardless of q and m — pure velocity filter.

m/s

6 Cyclotron — frequency & max KE

Fixed AC drives resonance

\[f_c = \dfrac{qB}{2\pi m},\quad K_{\max} = \dfrac{q^2 B^2 R^2}{2m}\]

Cannot accelerate: neutrons (no q) or electrons (relativistic mass rise breaks resonance).

Hz · J
B · Field due to Currents — Biot–Savart & Simple Geometries

7 Biot–Savart law

Element-level field

\[d\mathbf B = \dfrac{\mu_0}{4\pi}\dfrac{I\,d\mathbf l \times \hat r}{r^2}\]

μ₀/(4π) = 10⁻⁷ T·m/A · dB = 0 when dl ∥ r̂ (θ = 0 or π).

T

8 Infinite straight wire

⟂ distance a

\[B = \dfrac{\mu_0 I}{2\pi a}\]

Field lines are concentric circles by right-hand thumb rule.

T

9 Finite straight wire

θ₁, θ₂ from ⟂ at ends

\[B = \dfrac{\mu_0 I}{4\pi a}(\sin\theta_1 + \sin\theta_2)\]

Reduces to μ₀I/(2πa) when θ₁ = θ₂ = 90° (infinite wire limit).

T

10 Centre of circular coil (N turns)

Radius R

\[B = \dfrac{\mu_0 N I}{2R}\]

2R, NOT 2πR — classic trap. Direction ⟂ loop plane, right-hand curl.

T

11 Arc subtending φ (radians)

Fraction of a full loop

\[B = \dfrac{\mu_0 I \varphi}{4\pi R}\]

Semicircle (φ = π): μ₀I/(4R). Quarter: μ₀I/(8R). Full: μ₀I/(2R).

T

12 Axis of loop at distance x

Along the perpendicular axis

\[B = \dfrac{\mu_0 N I R^2}{2(R^2 + x^2)^{3/2}}\]

Recovers μ₀NI/(2R) at x = 0 · for x ≫ R: dipole approx \(B \approx \mu_0(2m)/(4\pi x^3)\).

T

13 Square loop of side a — centre

Sum of 4 finite-wire contributions

\[B = \dfrac{2\sqrt2\,\mu_0 I}{\pi a}\]

Derived from the finite-wire formula with each half-side subtending 45° at centre.

T
C · Ampère's Law & Its Applications

14 Ampère's circuital law

Around any closed loop

\[\oint \mathbf B\cdot d\mathbf l = \mu_0 I_{\text{enc}}\]

Line integral depends only on enclosed current — not on shape/size of loop or currents outside.

T·m

15 Long solenoid (inside)

n = turns per unit length

\[B = \mu_0 n I\]

Uniform inside, ~zero outside. At either end: μ₀nI/2. n = N/L.

T

16 Toroid

Total turns N, mean radius r

\[B = \dfrac{\mu_0 N I}{2\pi r}\]

B = 0 outside AND in the empty region enclosed by the ring. Only inside the ring is B ≠ 0.

T

17 Thick current cylinder (inside)

r < R

\[B = \dfrac{\mu_0 I r}{2\pi R^2}\]

Linear rise inside (0 at axis → μ₀I/(2πR) at surface), then 1/r decay outside.

T
D · Forces on Current-Carrying Conductors

18 Force on a straight wire

Vector form + magnitude

\[\mathbf F = I\mathbf L \times \mathbf B \;\Rightarrow\; F = BIL\sin\theta\]

Direction by right-hand rule (Fleming's left-hand rule for force). Net force on any closed loop in uniform B = 0.

N

19 Force between two parallel wires

Separation d

\[\dfrac{F}{L} = \dfrac{\mu_0 I_1 I_2}{2\pi d}\]

Same direction ⇒ attract · opposite ⇒ repel. Opposite of electrostatic same-charge rule.

N/m

20 Definition of ampere

SI base-unit definition

\[F/L = 2 \times 10^{-7}\;\text{N/m}\]

Force per metre between two infinitely long ∥ conductors 1 m apart, each carrying 1 A.

N/m at 1 A, 1 m apart
E · Magnetic Moment · Torque · Dipole

21 Magnetic moment of a loop

N turns · area A

\[m = NIA,\;\; \mathbf m = NI\mathbf A\]

Direction ⟂ loop plane by right-hand curl rule (curl fingers in direction of I, thumb = m).

A·m²

22 Torque on loop in B

Uniform field

\[\boldsymbol\tau = \mathbf m \times \mathbf B,\;\; \tau = NIAB\sin\theta\]

θ = angle between m and B. τ max when loop-plane ∥ B (m ⟂ B). τ = 0 when plane ⟂ B (m ∥ B).

N·m

23 PE of magnetic dipole

Signed by orientation

\[U = -\mathbf m\cdot\mathbf B = -mB\cos\theta\]

Stable eqm at θ = 0 (U min). Unstable at θ = π (U max).

J

24 Revolving electron — magnetic moment

Orbital contribution

\[\mu_l = \dfrac{evr}{2} = \dfrac{e}{2m_e}\,L\]

Gyromagnetic ratio e/2m_e ≈ 8.8 × 10¹⁰ C/kg. L = orbital angular momentum.

A·m²

25 Bohr magneton

Natural atomic magnetic-moment unit · smallest orbital moment (n = 1)

\[\mu_B = \dfrac{eh}{4\pi\, m_e} = \dfrac{e\hbar}{2 m_e} \approx 9.27 \times 10^{-24}\ \text{J T}^{-1}\]

Derivation: for smallest Bohr orbit L = ℏ = h/(2π); substitute into μl = (e/2me) L. All atomic magnetic moments are quoted as multiples of μB. Unit: 1 J T−1 = 1 A m2.

J T⁻¹ = A m²
F · Moving Coil Galvanometer & Conversions

26 Restoring balance

k = torsional constant

\[k\theta = NIAB \;\Rightarrow\; \theta = \dfrac{NAB}{k}\,I\]

Deflection θ is linearly proportional to I.

rad

27 Current sensitivity

Deflection per unit current

\[\dfrac{\theta}{I} = \dfrac{NAB}{k}\]

Raise N ⇒ raises CS. But also raises coil R.

rad/A

28 Voltage sensitivity

R = coil resistance

\[\dfrac{\theta}{V} = \dfrac{NAB}{k R}\]

Raising N raises CS but also R ⇒ VS may not rise. Classic NEET trap.

rad/V

29 Galvanometer → Ammeter

Shunt in parallel

\[S = \dfrac{I_g\,G}{I - I_g}\]

S is small (parallel) · connect ammeter in series with the load · ideal ammeter: R → 0.

Ω

30 Galvanometer → Voltmeter

High-value R in series

\[R_s = \dfrac{V}{I_g} - G\]

R_s is large (series) · connect voltmeter in parallel across element · ideal voltmeter: R → ∞.

Ω
G · Quick Reference — Constants & Standard Values
μ₀ = 4π × 10⁻⁷ T·m·A⁻¹ ·   μ₀/(4π) = 10⁻⁷ T·m·A⁻¹ ·   e = 1.6 × 10⁻¹⁹ C ·   m_e = 9.1 × 10⁻³¹ kg ·   m_p = 1.67 × 10⁻²⁷ kg (≈ 1836 m_e)
Bohr magneton μ_B = 9.27 × 10⁻²⁴ A·m² ·   Gyromagnetic ratio e/2m_e ≈ 8.8 × 10¹⁰ C·kg⁻¹
Earth's magnetic field ~ 30–60 μT ·   Force per m between 1-A parallel wires 1 m apart = 2 × 10⁻⁷ N/m ·   Cyclotron freq of proton in 1 T ≈ 15.2 MHz

📊 PYQ Weightage Map — Last 10–15 Years ≈ 3 Q/yr

Ranked by how often NEET has pulled from each sub-topic (2010–2024). MCM sits in the top-4 highest-yield Physics chapters — Lorentz force + circular motion combinations dominate.

1. Force on a charged particle · circular motion in B (\(r = mv/qB\))
🔥🔥🔥🔥🔥
≈ 1 Q/yr · protons vs α-particle traps
2. Biot-Savart applications — centre of loop / arc / straight wire
🔥🔥🔥🔥🔥
≈ 1 Q/yr · 2R vs 2πR trap
3. Ampere's law — solenoid & toroid (\(B = \mu_0 n I\))
🔥🔥🔥🔥🔥
Inside vs outside toroid; end of solenoid
4. Torque on current loop & magnetic moment
🔥🔥🔥🔥🔥
τ = NIAB sinθ; stable/unstable eqm
5. Force on current-carrying wire · parallel-wire force
🔥🔥🔥🔥🔥
Attract vs repel; define ampere
6. Cyclotron — frequency, K_max, limitations
🔥🔥🔥🔥🔥
Can't accelerate neutron/electron
7. Moving-coil galvanometer → ammeter/voltmeter conversion
🔥🔥🔥🔥🔥
Shunt in parallel; series R for V
8. Current sensitivity vs voltage sensitivity
🔥🔥🔥🔥🔥
Adding turns raises CS but maybe not VS
9. Helical path · velocity selector (\(v = E/B\))
🔥🔥🔥🔥🔥
Pitch = v cosθ · T
10. Magnetic dipole moment of revolving electron · Bohr magneton
🔥🔥🔥🔥🔥
μ_B = 9.27 × 10⁻²⁴ A m²
11. Field at axis of a coil (\(x \gg R\) dipole approx)
🔥🔥🔥🔥🔥
Rare direct Q
12. Square/polygonal loop field derivations
🔥🔥🔥🔥🔥
2√2 μ₀I/πa for side a
🔥 Priority order: Lorentz + circular motion → Biot-Savart (loop/arc/wire) → Ampere (solenoid/toroid) → Torque on loop → Parallel wires → Cyclotron → Galvanometer. Master the first four blocks and you lock ~ 2.5 of 3 chapter Qs almost every NEET.

🧮 Master Formula Sheet Every symbol · unit · condition

A · Magnetic field due to currents 🔥🔥🔥🔥🔥
SituationFormulaSymbols · Units · Condition
Biot-Savart\[d\mathbf B = \dfrac{\mu_0}{4\pi}\dfrac{I\,d\mathbf l \times \hat r}{r^2}\]μ₀ = 4π×10⁻⁷ T·m·A⁻¹ · I in A · dl in m · r in m · dB in T · zero when dl ∥ r̂ (θ = 0 or π)
Infinite straight wire\[B = \dfrac{\mu_0 I}{2\pi a}\]a = ⟂ distance from wire · field lines concentric circles · right-hand thumb rule
Finite straight wire\[B = \dfrac{\mu_0 I}{4\pi a}(\sin\theta_1 + \sin\theta_2)\]θ₁, θ₂ measured from ⟂ to wire at the two ends
Centre of circular coil\[B = \dfrac{\mu_0 N I}{2R}\]N turns · R = radius · 2R not 2πR (classic trap)
Arc subtending φ (rad)\[B = \dfrac{\mu_0 I \varphi}{4\pi R}\]Semicircle (φ = π) → \(B = \mu_0 I/4R\); quarter circle → \(\mu_0 I/8R\)
Axis of loop (distance x)\[B = \dfrac{\mu_0 N I R^2}{2(R^2 + x^2)^{3/2}}\]x = distance along axis · at x=0 recovers centre formula · x ≫ R: \(B \approx \mu_0 (2m)/(4\pi x^3)\) (dipole)
Square loop of side a (at centre)\[B = \dfrac{2\sqrt2\,\mu_0 I}{\pi a}\]Sum of 4 finite-wire contributions
Ampere's law\[\oint \mathbf B\cdot d\mathbf l = \mu_0 I_{\text{enc}}\]Line integral around any closed loop = μ₀ × enclosed current · shape-independent
Long solenoid (inside)\[B = \mu_0 n I\]n = turns per unit length · uniform inside, ~zero outside. At either end: μ₀nI/2
Toroid\[B = \dfrac{\mu_0 N I}{2\pi r}\]N = total turns · r = mean radius · B = 0 outside AND in the empty region inside the ring
Thick cylindrical conductor (inside)\[B = \dfrac{\mu_0 I r}{2\pi R^2}\;(r < R)\]Linear rise inside · 1/r outside
B · Motion of a charged particle 🔥🔥🔥🔥🔥
QuantityFormulaSymbols · Notes
Lorentz force\[\mathbf F = q(\mathbf E + \mathbf v \times \mathbf B)\]Magnetic part ⊥ v ⇒ no work; speed & KE constant · Newton on unit charge
Radius (v ⊥ B)\[r = \dfrac{mv}{qB} = \dfrac{p}{qB} = \dfrac{\sqrt{2mK}}{qB}\]Also \(r = \dfrac{1}{B}\sqrt{\dfrac{2mV}{q}}\) if accelerated through V
Period · frequency · ω\[T = \dfrac{2\pi m}{qB},\; f = \dfrac{qB}{2\pi m},\; \omega = \dfrac{qB}{m}\]All independent of v and r — cyclotron principle
Helical path (angle θ to B)\[\text{pitch} = v\cos\theta \cdot T = \dfrac{2\pi m v\cos\theta}{qB}\]Radius uses only v⊥ = v sinθ
Velocity selector (crossed E, B)\[v = \dfrac{E}{B}\]Undeviated · regardless of q and m
Cyclotron\[f = \dfrac{qB}{2\pi m},\; K_{\max} = \dfrac{q^2 B^2 R^2}{2m}\]R = dee radius · cannot accelerate n (no q) or e⁻ (relativistic)
C · Force · torque · magnetic dipole 🔥🔥🔥🔥
QuantityFormulaSymbols · Notes
Force on current-carrying wire\[\mathbf F = I\mathbf L \times \mathbf B \Rightarrow F = BIL\sin\theta\]L = length vector along current · net force on closed loop in uniform B = 0
Force between parallel wires\[\dfrac{F}{L} = \dfrac{\mu_0 I_1 I_2}{2\pi d}\]Same direction ⇒ attract · opposite ⇒ repel · d = separation
Definition of ampere\[F/L = 2\times 10^{-7}\text{ N/m}\]Between two ∥ wires 1 m apart, each carrying 1 A
Magnetic moment (loop)\[m = NIA,\; \mathbf m = NI\mathbf A\]Direction ⟂ loop plane by right-hand curl rule · SI unit: A·m²
Torque on loop in B\[\boldsymbol\tau = \mathbf m \times \mathbf B \Rightarrow \tau = NIAB\sin\theta\]θ = angle between m and B · τ max when loop-plane ∥ B; τ = 0 when plane ⟂ B
PE of dipole\[U = -\mathbf m\cdot\mathbf B = -mB\cos\theta\]Stable at θ = 0 (U min); unstable at θ = π
Revolving electron (μl)\[\mu_l = \dfrac{evr}{2} = \dfrac{e}{2 m_e}\,L\]Gyromagnetic ratio e/(2me) ≈ 8.8 × 10¹⁰ C·kg⁻¹
Bohr magneton\[\mu_B = \dfrac{eh}{4\pi\, m_e} = \dfrac{e\hbar}{2 m_e} \approx 9.27 \times 10^{-24}\ \text{J T}^{-1}\]Smallest orbital moment (n = 1) · 1 J T⁻¹ = 1 A m²
D · Moving coil galvanometer 🔥🔥🔥
QuantityFormulaNotes
Restoring torque\[k\theta = NIAB \Rightarrow \theta = \dfrac{NAB}{k}\cdot I\]k = torsional const. · θ = deflection · A = coil area
Current sensitivity\[\dfrac{\theta}{I} = \dfrac{NAB}{k}\]Deflection per unit current
Voltage sensitivity\[\dfrac{\theta}{V} = \dfrac{NAB}{kR}\]R = coil resistance · raising N raises CS but also R ⇒ VS may not rise
Galvanometer → Ammeter\[S = \dfrac{I_g\, G}{I - I_g}\]Shunt S in parallel; low S · connect in series with load
Galvanometer → Voltmeter\[R_s = \dfrac{V}{I_g} - G\]High-value R in series; connect in parallel with element

📐 Key Derivations (pivot points)

Field at centre of circular loop (from Biot-Savart)
Start: \(d\mathbf B = \dfrac{\mu_0}{4\pi}\dfrac{I\,d\mathbf l\times\hat r}{r^2}\). For every element, \(d\mathbf l \perp \hat r\) so \(|d\mathbf l\times\hat r| = dl\), and every dB is along the axis. Integrate around circle: \(\oint dl = 2\pi R\). Result: \(B = \dfrac{\mu_0 I(2\pi R)}{4\pi R^2} = \dfrac{\mu_0 I}{2R}\).
Ampere's law → solenoid field
Amperian loop: rectangle with one long side of length L inside solenoid (parallel to axis), the parallel side outside (B≈0), short sides ⟂ to B. Only the inside side contributes: \(\oint \mathbf B\cdot d\mathbf l = BL\). Enclosed current: \(nL\cdot I\). Result: \(BL = \mu_0 nLI \Rightarrow B = \mu_0 nI\).
Force between two parallel wires
Wire 1 produces \(B_1 = \dfrac{\mu_0 I_1}{2\pi d}\) at wire 2. Force on length L of wire 2: \(F = I_2 L B_1 = \dfrac{\mu_0 I_1 I_2 L}{2\pi d}\). Same direction ⇒ B field lines encircle both wires so the wires "pull" toward each other ⇒ attract. Opposite ⇒ repel.
Torque on current loop
Rectangular loop, sides a·b, in uniform B. Forces on the two sides ∥ B are zero. Forces on the two sides ⟂ B are equal & opposite (F = BIa) but at distance b apart. Torque = F · b sinθ = BI(ab)sinθ = BIA sinθ. For N turns: τ = NIAB sinθ. Vector form: \(\boldsymbol\tau = \mathbf m \times \mathbf B\) with m = NIA.
Cyclotron frequency
Radius equation: \(r = mv/qB\). Period T: \(T = 2\pi r/v = 2\pi m/qB\). Notice: T does not contain v or r ⇒ the particle takes the same time for every half-circle regardless of speed. That's why a fixed-frequency AC voltage between the dees keeps it in resonance. f_c = qB/2πm.

💡 Concept Essentials

🎯 Problem Types & Methods

(a) 🔥 Radius/period of a charged particle in B
Given: q, m, v (or K or V), B. Ask: r or T. Method: Pick the right radius form — if v given: r = mv/qB; if K given: r = √(2mK)/qB; if accelerated through V: r = (1/B)√(2mV/q). T = 2πm/qB (no v!). For α vs proton: same K ⇒ r_α/r_p = √(m_α/m_p) × (q_p/q_α) = √4 × (1/2) = 1 (surprising equality).
(b) 🔥 Field due to Biot-Savart configurations
Step 1: Break the wire path into standard pieces (finite wires + arcs). Step 2: Apply the piece-specific formula (μ₀I/2πa for straight, μ₀Iφ/4πR for arc, 0 for radial pieces where dl ∥ r̂). Step 3: Add vectorially — usually all pieces contribute along the same axis so it's just algebra.
(c) 🔥 Ampere's law — solenoid / toroid / cylinder
Solenoid inside: B = μ₀nI. Solenoid at end: B = μ₀nI/2. Toroid inside: B = μ₀NI/(2πr). Toroid outside / inside empty region: B = 0. Thick cylinder (r < R): B = μ₀Ir/(2πR²) (linear in r); r > R: μ₀I/(2πr).
(d) 🔥 Torque on rectangular / circular loop
Compute m = NIA (unit-vector normal to plane by right-hand curl). Then τ = mB sinθ where θ is angle between m and B. If the coil "plane is parallel to B", θ = 90° ⇒ τ = mB (max). If "plane is perpendicular to B", θ = 0° ⇒ τ = 0 (but this is stable equilibrium).
(e) Force between parallel wires
F/L = μ₀I₁I₂/(2πd). Same direction currents → attract. Opposite → repel. For grids of wires, add pairwise force contributions vectorially.
(f) Galvanometer conversion
For ammeter of full-scale I: S = I_g G/(I − I_g). For voltmeter of full-scale V: R_s = V/I_g − G. Ideal ammeter: R → 0 (shunt very small); ideal voltmeter: R → ∞ (series R very large).
(g) Cyclotron numericals
f = qB/(2πm). K_max = q²B²R²/(2m). Use q and m of the specific ion (proton, deuteron, α, etc.). To double K_max at fixed B ⇒ double R only if same particle.
(h) Helical path pitch
If v is at angle θ to B: r = mv sinθ/(qB) (uses perpendicular component); pitch = v cosθ · T = 2πm v cosθ/(qB).

⚖️ Constant-vs-Changes Tables

(a) Particle in a magnetic field — as B is changed
QuantityBehaviour
Speed |v|Unchanged (B does no work)
KEUnchanged
Radius r = mv/qB↓ as B ↑ (inversely proportional)
Period T = 2πm/qB↓ as B ↑ (inversely proportional)
Frequency↑ as B ↑
(b) Solenoid — as n or I changes
ChangeEffect on B = μ₀nI
Double n (turns/m)B doubles
Double IB doubles
Double length (same total N)n halves ⇒ B halves
Change radiusNo effect (inside long solenoid)
(c) Cyclotron — as B or v changes
ChangeEffect
Increase v (same B)r increases · T unchanged · K_max reached later
Increase B (same v)r decreases · T decreases · f increases
Increase R (dee size)K_max increases as R²

📈 Graphs to Know

GraphShapeMeaning
B vs r for straight wireHyperbola (B ∝ 1/r) for r > wire radiusμ₀I/(2πr) outside · linear inside for thick wire
B vs r for thick current cylinderLinear rise inside (0 → μ₀I/2πR at r = R), then 1/r decay outsideKink at r = R
B vs x on axis of loopPeaks at centre (x = 0), falls to zero as x → ∞Decays as 1/x³ for x ≫ R (dipole)
B along axis of solenoidNearly uniform μ₀nI inside, drops to μ₀nI/2 at each end, → 0 far outsideConstant plateau interior
B for toroidZero outside AND in central hole; ≠ 0 only inside the ring1/r inside the ring
τ vs θ (loop in B)Sinusoid — max at θ = 90°, zero at 0 and 180°Slope at θ = 0 gives restoring const
U vs θ (loop in B)Cosine: min at θ = 0 (stable), max at θ = π (unstable)U = −mB cosθ

🧷 Units & Dimensions

QuantitySI unitDimensional formula
Magnetic field Btesla (T) = kg·A⁻¹·s⁻² = Wb·m⁻²[M T⁻² A⁻¹]
Magnetic flux Φweber (Wb) = T·m² = V·s[M L² T⁻² A⁻¹]
Magnetic moment mA·m²[A L²]
Permeability μ₀T·m·A⁻¹ = N·A⁻²[M L T⁻² A⁻²]
Current sensitivity (θ/I)rad·A⁻¹[A⁻¹]
Voltage sensitivity (θ/V)rad·V⁻¹[M⁻¹ L⁻² T³ A]
Torsional constant kN·m·rad⁻¹[M L² T⁻²]
Cyclotron frequencyHz[T⁻¹]

🔢 Standard Values

Constant / valueValue
μ₀ (permeability of vacuum)4π × 10⁻⁷ T·m·A⁻¹
μ₀/(4π)10⁻⁷ T·m·A⁻¹
Electron charge e1.6 × 10⁻¹⁹ C
Electron mass m_e9.1 × 10⁻³¹ kg
Proton mass m_p1.67 × 10⁻²⁷ kg (≈ 1836 m_e)
Bohr magneton μ_B9.27 × 10⁻²⁴ A·m²
Gyromagnetic ratio e/2m_e≈ 8.8 × 10¹⁰ C·kg⁻¹
Earth's magnetic field (typical)~ 30–60 μT (3–6 × 10⁻⁵ T)
Force per m between 1 A parallel wires (1 m apart)2 × 10⁻⁷ N·m⁻¹
Cyclotron freq of proton in 1 T≈ 15.2 MHz

Shortcuts & Sign Rules

⚠️ Trap Points / Common Mistakes

2R vs 2πR — loop centre uses 2R, straight wire uses 2πa. The single most common slip.
Magnetic force does NO work. Never write "work = Fd" for a pure magnetic force.
T is independent of v (and r). Fast particles just make bigger circles in the same time.
Net force on a closed loop in uniform B = 0. Only torque exists. In non-uniform B, net force appears.
Current sensitivity vs voltage sensitivity. Adding turns raises CS AND R — so VS may not rise.
Sign flip for electron. Direction of F for +ve charge — then reverse for e⁻.
Cyclotron can't accelerate neutrons (no q) or electrons (relativistic mass rise breaks resonance).
Solenoid end field = μ₀nI/2 (not μ₀nI). Full field only deep inside.
Toroid outside and in the empty central hole → B = 0. Only inside the ring is B ≠ 0.
Torque max when plane ∥ B, not when plane ⟂ B. The plane ⟂ B is stable eqm (τ = 0).
Ammeter — shunt in PARALLEL (small R). Voltmeter — R in SERIES (large R). Don't swap.
Ampere's law is always true — but only useful when symmetry lets you pull B out of the integral.

🧭 Direction Drill — Right-Hand & Fleming Rules Zero-error subject

The three rules — which to use when

Rule 1 Right-hand curl rule Use for: B produced by a current (wire, loop, solenoid). Thumb = current direction (I) · fingers curl = direction of B.
Rule 2 Fleming's left-hand rule (FBI) Use for: force on a current-carrying wire in a field. ForeFinger = B · Middle = I (current) · Thumb = F (force). Order: F-B-I.
Rule 3 Fleming's right-hand rule Use for: induced current in a moving conductor (EMI). Same layout: ForeFinger = B · Thumb = v (motion) · Middle = induced I.
Rule 4 Right-hand slap / palm rule Use for: force on a positive charge moving in B. Fingers point in v · curl into B · thumb gives F. For negative charge, reverse the answer.

10 quick drill Qs — 30 seconds each

  1. Current flows north (→) in a wire. Where does B point directly above the wire?
    AnswerWest (out of page if looking down). Curl right-hand fingers: thumb north → above the wire, fingers point west.
  2. Positive charge moves east (→); B points north. Force direction?
    AnswerVertically up (out of ground). F = qv×B. Fingers east, curl to north, thumb up.
  3. Same as Q2 but negative charge — force?
    AnswerVertically down. Negative charge → reverse the answer.
  4. Circular loop lies flat, current flows clockwise when viewed from above. B at centre points?
    AnswerDownward (into the ground). Curl fingers clockwise → thumb points down.
  5. Two parallel wires · both carry current north. Force on each?
    AnswerAttract each other. Same-direction currents attract.
  6. An electron enters a B field pointing right (→) with velocity into the page (⊗). Force?
    AnswerUpward. For +q: v×B = (⊗)×(→) = ↓, but electron is negative → force is up.
  7. Straight wire vertical, current up. B at a point to your right?
    AnswerPoints away from you (into page). Thumb up, fingers curl → at right side, B goes into page.
  8. Rectangular loop in a horizontal B field, loop plane is horizontal. Torque?
    AnswerZero. Loop plane ∥ B means m ⟂ B — wait: plane ∥ B means area vector m ⟂ B → sinθ = 1 → torque is MAX, not zero. Trap. τ = 0 only when loop plane ⟂ B (m ∥ B).
  9. Solenoid current flows counter-clockwise when you look at its right end. Which end is N pole?
    AnswerLeft end is N. Curl right-hand fingers with current at right end (counter-clockwise) → thumb points LEFT → left = N.
  10. Cyclotron: proton is accelerating. Radius changes but period is …?
    AnswerConstant. T = 2πm/qB — independent of v and r. This is why the D-gap oscillator frequency is fixed.

Torque angle trap

Formula: τ = NIAB sinθ, where θ = angle between area vector m and B.
  • Loop plane ∥ B (m ⟂ B, θ = 90°) → sinθ = 1 → τ MAX
  • Loop plane ⟂ B (m ∥ B, θ = 0°) → sinθ = 0 → τ = ZERO — stable equilibrium
  • m antiparallel to B (θ = 180°) → sinθ = 0 → τ = 0 but unstable equilibrium
🚩 The wording trap: "loop plane parallel" is where torque is MAX, not zero. NEET's #1 confusion in this chapter.

🧠 Mnemonics

Loop vs wire coefficient — "Loop is 2R (round trip 2 arms), wire is 2πR (full round)." Loops have a diameter; wires have a circumference.
Cyclotron independence — "Time same, radius grows." T = 2πm/qB has no v or r in it.
Torque max/zero — "Plane parallel = torque maximum · Plane perpendicular = torque zero." Or: "m along B = zero, m ⟂ B = max."
Parallel wires — "Same-way = friends (attract); opposite-way = enemies (repel)."
Ammeter vs voltmeter — "Ammeter loves company (parallel shunt), Voltmeter goes solo (series R)."
Radius formulas — "Momentum divided by charge-B" (r = p/qB). Then swap p in for √(2mK) or √(2mqV).
Cyclotron limits — "No neutron (no charge), no electron (goes relativistic)."
Right-hand pointer — "Thumb = I, curl = B" (fields). "Fingers = v, curl into B, thumb = F" (forces on +q).

🔗 Cross-Chapter Links

🎯 High-Yield Top 15 Master these first

  1. Radius: r = mv/qB = p/qB = √(2mK)/qB = (1/B)√(2mV/q).
  2. Period T = 2πm/qB, f = qB/(2πm) — independent of v and r.
  3. B at centre of loop = μ₀NI/(2R). B due to straight wire = μ₀I/(2πa).
  4. Arc of angle φ: B = μ₀Iφ/(4πR). Semicircle: μ₀I/(4R).
  5. Solenoid inside: B = μ₀nI · At the end: μ₀nI/2 · Outside: ≈ 0.
  6. Toroid: B = μ₀NI/(2πr) inside the ring · zero outside and in the central hole.
  7. Force on wire: F = IL × B, magnitude BIL sinθ. Net force on closed loop in uniform B = 0.
  8. Parallel wires: F/L = μ₀I₁I₂/(2πd). Same direction ⇒ attract; opposite ⇒ repel.
  9. Torque on loop: τ = NIAB sinθ = m × B. Max when plane ∥ B; zero when plane ⟂ B.
  10. PE: U = −mB cosθ. Stable at θ = 0, unstable at θ = π.
  11. Velocity selector: v = E/B (undeviated for any q, m).
  12. Helical pitch: 2πm v cosθ/(qB). Radius uses v sinθ.
  13. Cyclotron K_max = q²B²R²/(2m). Cannot accelerate neutrons or electrons.
  14. Bohr magneton = 9.27 × 10⁻²⁴ A·m². Gyromagnetic ratio e/2m ≈ 8.8 × 10¹⁰ C/kg.
  15. Galvanometer: ammeter shunt S = I_g·G/(I − I_g) [parallel] · voltmeter series R = V/I_g − G.

📝 Graded Self-Test — 15 NEET MCQs

Q1. A proton and an α-particle enter a magnetic field with the same kinetic energy. The ratio r_α : r_p is:
(a) 1 : 1 (b) 2 : 1 (c) √2 : 1 (d) 1 : 2
Answer(a) 1 : 1. r = √(2mK)/qB. Ratio = √(m_α/m_p) × (q_p/q_α) = √4 × (1/2) = 1.
Q2. A charged particle moving in a magnetic field experiences no force. This means:
(a) B = 0 (b) v = 0 (c) v ∥ B (d) any of these
Answer(d) any of these. F = qv × B is zero if B = 0, v = 0, or v ∥ B (θ = 0 or π).
Q3. A circular loop of radius 0.1 m carries 2 A. B at centre?
(a) 1.26 × 10⁻⁵ T (b) 4π × 10⁻⁵ T (c) 2π × 10⁻⁵ T (d) 2 × 10⁻⁵ T
Answer(a) B = μ₀I/(2R) = (4π × 10⁻⁷)(2)/(2 × 0.1) = 4π × 10⁻⁶ ≈ 1.26 × 10⁻⁵ T.
Q4. A long solenoid has 500 turns per metre and carries 4 A. B inside:
(a) 2.51 × 10⁻³ T (b) 6.28 × 10⁻³ T (c) 8π × 10⁻⁴ T (d) 1.6π × 10⁻³ T
Answer(a) B = μ₀nI = (4π × 10⁻⁷)(500)(4) = 8π × 10⁻⁴ ≈ 2.51 × 10⁻³ T.
Q5. A circular coil of 100 turns, area 0.05 m², carries 2 A. Placed in a 0.4 T field. Max torque:
(a) 4 N·m (b) 40 N·m (c) 0.4 N·m (d) 400 N·m
Answer(a) τ_max = NIAB = 100 × 2 × 0.05 × 0.4 = 4 N·m.
Q6. The magnetic moment of the coil in Q5:
(a) 10 A·m² (b) 100 A·m² (c) 200 A·m² (d) 0.1 A·m²
Answer(a) m = NIA = 100 × 2 × 0.05 = 10 A·m².
Q7. Two long parallel wires 20 cm apart carry 10 A each in the same direction. Force per metre on each:
(a) 10⁻⁴ N/m attract (b) 10⁻⁴ N/m repel (c) 2 × 10⁻⁵ N/m attract (d) 10⁻⁵ N/m attract
Answer(a) F/L = μ₀I₁I₂/(2πd) = (2 × 10⁻⁷)(10)(10)/(0.20) = 10⁻⁴ N/m. Same direction ⇒ attract.
Q8. Cyclotron with B = 1 T, dee radius 0.5 m. Max KE of proton (m = 1.67 × 10⁻²⁷ kg, q = 1.6 × 10⁻¹⁹ C)?
(a) ≈ 12 MeV (b) ≈ 6 MeV (c) ≈ 120 keV (d) ≈ 1.2 GeV
Answer(a) K_max = q²B²R²/(2m) = (1.6e-19)²(1)²(0.5)²/(2 × 1.67e-27) ≈ 1.92 × 10⁻¹² J ≈ 12 MeV.
Q9. An electron and a proton enter a magnetic field perpendicular to their motion with the same speed. Ratio of periods T_e : T_p:
(a) m_e / m_p (b) m_p / m_e (c) 1 : 1 (d) √(m_e/m_p)
Answer(a) T = 2πm/qB, both have same |q|, so T ∝ m ⇒ T_e/T_p = m_e/m_p ≈ 1/1836.
Q10. Galvanometer of G = 100 Ω, full-scale I_g = 10 mA. Convert to ammeter for 5 A. Shunt:
(a) 0.02 Ω (b) 0.2 Ω (c) 2 Ω (d) 20 Ω
Answer(b) S = I_g G/(I − I_g) = (10⁻²)(100)/(5 − 10⁻²) ≈ 1/5 = 0.2 Ω.
Q11. A circular loop of area A carries current I. If bent into two loops each of area A/2 (semicircles superposed), the magnetic moment:
(a) halves (b) doubles (c) unchanged (d) becomes zero
Answer(c) m = NIA. Now N = 2, A_each = A/2, so m = 2 × I × (A/2) = IA. Unchanged.
Q12. A charged particle enters a magnetic field at 60° to B with speed v. The pitch of the helix is:
(a) 2πm v cos60°/(qB) (b) 2πm v sin60°/(qB) (c) 2πm v/(qB) (d) πm v/(qB)
Answer(a) pitch = v_∥ · T = v cos60° · 2πm/(qB).
Q13. A rectangular loop lies in a magnetic field with its plane parallel to B. Then:
(a) net force zero, torque zero (b) net force zero, torque max (c) net force max, torque zero (d) both max
Answer(b) Uniform B: net force on any closed loop = 0. Plane ∥ B ⇒ m ⟂ B ⇒ θ = 90° ⇒ τ = NIAB (maximum).
Q14. A toroid has 500 total turns and mean radius 10 cm. Current 2 A. Field inside the ring:
(a) 2 × 10⁻³ T (b) 4π × 10⁻³ T (c) 10⁻³ T (d) 5 × 10⁻⁴ T
Answer(a) B = μ₀NI/(2πr) = (4π × 10⁻⁷)(500)(2)/(2π × 0.10) = 2 × 10⁻³ T.
Q15. Assertion: A cyclotron cannot accelerate an electron. Reason: The relativistic mass increase causes the cyclotron frequency to fall out of resonance with the AC voltage.
(a) Both true, R explains A (b) Both true, R doesn't explain (c) A true, R false (d) A false, R true
Answer(a) Both true and connected. At even modest energies (few keV), the electron's relativistic mass grows enough that ω_c = qB/m keeps decreasing, breaking phase-lock with the fixed AC frequency.

Card built 2026-07-26 for NEET drill practice · Chapter 4 · Moving Charges and Magnetism · Strictly NCERT-scoped · Weightage rankings reflect 10–15 years of NEET / AIPMT PYQ frequency.